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A 5 % solution (w/W) of cane sugar (molar mass =342g mol−1) has freezing point 271K. What will be the freezing point of 5 % glucose (molar mass = 18g mol−1) in water if freezin$(ii) The freezing point of a solution of 3.42g of cane sugar (molecular weight=342) in 100g water is −0.185oC . The freezing point of a solution of 12.5g N H 4Cl molecular weight!What would be the freezing point of an aqueous solution containing 17 g of C2H 5OH in 1000 g of water. KfH2O = 1.86 K m−1: View Solution+The freezing point of any substance describes the point for the liquid to solid transition. The liquids can be super-cooled beyond their freezing points so that they dont solidify#The freezing point of one molal NaCl solution assuming NaCl to be 100% dissociated in water is (molal depression constant = 1.86)~The correct option is C 1% CaCl2 Depression in freezing point is a colligative property. Thus, the compounds which produce maximum ions has the least freezing point.%The freezing point of pure nitro benzene is 278.8K. When 2.5 g of an unknown substance is dissolved in 100 g of nitrobenzene, the freezing point of the solution was found to be 276